A, heater power or freezing power KW = W×△t×C×S/860×T
W= mold weight or cooling water KG
t= the temperature difference between the desired temperature and the starting temperature.
C= specific heat oil (0.5), steel (0.11), water (1), plastic (0.45~0.55)
B, find the size of the pump
Need to know the customer's required pump flow and pressure (head)
P(pressure Kg/cm2)=0.1×H(head M)×α(specific gravity of heat transfer media, water =1, oil =0.7-0.9)
L(media required flow L/min)=Q(mold required heat Kcal/H)/C(media ratio of hot water =1 oil =0.45)×t(temperature difference between circulating media and mold)×α×60
2. Freezer capacity selection
A, Q(freezing quantity Kcal/H)=Q1+Q2
Q1(Heat Kcal/H of raw materials into the mold)=W(weight KG of raw materials injected into the mold per hour)×C×(T1-T2)×S(** coefficient 1.5~2)
T1 temperature of the raw material in the material tube; T2 Temperature when the finished product is taken out of the mold
Q2 Heat generated by hot runner Kcal/H
B, quick calculation method (not applicable to hot runner)
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